Searched refs:Nd (Results 1 – 6 of 6) sorted by relevance
302 C = Nd * (Nc + Ns)304 其中：Nd是性能域的数量；Nc是CPU的数量；Ns是OPP的总数（例如：对于两个性能域，
173 unsigned char Nd; /* max # of Domains - 1 */ member
34 Proceedings of the 32Nd ACM SIGPLAN Conference on Programming
256 if (ap_qci_info->Nd) { in ap_init_qci_info()257 ap_max_domain_id = ap_qci_info->Nd; in ap_init_qci_info()
598 matrix->aqm_max = info->apxa ? info->Nd : 15; in vfio_ap_matrix_init()599 matrix->adm_max = info->apxa ? info->Nd : 15; in vfio_ap_matrix_init()
367 C = Nd * (Nc + Ns)369 with: Nd the number of performance domains; Nc the number of CPUs; and Ns the