Searched refs:op_p (Results 1 – 3 of 3) sorted by relevance
554 const struct sysrq_key_op *op_p = NULL; in __sysrq_get_key_op() local559 op_p = sysrq_key_table[i]; in __sysrq_get_key_op()561 return op_p; in __sysrq_get_key_op()564 static void __sysrq_put_key_op(int key, const struct sysrq_key_op *op_p) in __sysrq_put_key_op() argument569 sysrq_key_table[i] = op_p; in __sysrq_put_key_op()574 const struct sysrq_key_op *op_p; in __handle_sysrq() local593 op_p = __sysrq_get_key_op(key); in __handle_sysrq()594 if (op_p) { in __handle_sysrq()599 if (!check_mask || sysrq_on_mask(op_p->enable_mask)) { in __handle_sysrq()600 pr_info("%s\n", op_p->action_msg); in __handle_sysrq()[all …]
231 ``register_sysrq_key(int key, const struct sysrq_key_op *op_p);``，232 该函数在表中的 'key' 对应位置内容是空的情况下，将通过 ``op_p`` 指针注册这个操作234 ``unregister_sysrq_key(int key, const struct sysrq_key_op *op_p)`` 函数，该函数235 只有在当前该键对应的处理函数被注册到了 'key' 对应位置时，才会移除 'op_p' 指针
238 ``register_sysrq_key(int key, const struct sysrq_key_op *op_p);`` this will239 register the operation pointed to by ``op_p`` at table key 'key',241 the function ``unregister_sysrq_key(int key, const struct sysrq_key_op *op_p)``,242 which will remove the key op pointed to by 'op_p' from the key 'key', if and