Searched refs:rx_skb_i (Results 1 – 1 of 1) sorted by relevance
355 u8 rx_skb_i, rx_skb_o; member376 while ((((u8)(pd->rx_skb_i - pd->rx_skb_o)) < S6_NUM_RX_SKB) && in s6gmac_rx_fillfifo()379 pd->rx_skb[(pd->rx_skb_i++) % S6_NUM_RX_SKB] = skb; in s6gmac_rx_fillfifo()390 while (((u8)(pd->rx_skb_i - pd->rx_skb_o)) > in s6gmac_rx_interrupt()925 while (pd->rx_skb_i != pd->rx_skb_o) in s6gmac_stop()