1 /**
2 * eCryptfs: Linux filesystem encryption layer
3 * Functions only useful for debugging.
4 *
5 * Copyright (C) 2006 International Business Machines Corp.
6 * Author(s): Michael A. Halcrow <mahalcro@us.ibm.com>
7 *
8 * This program is free software; you can redistribute it and/or
9 * modify it under the terms of the GNU General Public License as
10 * published by the Free Software Foundation; either version 2 of the
11 * License, or (at your option) any later version.
12 *
13 * This program is distributed in the hope that it will be useful, but
14 * WITHOUT ANY WARRANTY; without even the implied warranty of
15 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
16 * General Public License for more details.
17 *
18 * You should have received a copy of the GNU General Public License
19 * along with this program; if not, write to the Free Software
20 * Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA
21 * 02111-1307, USA.
22 */
23
24 #include "ecryptfs_kernel.h"
25
26 /**
27 * ecryptfs_dump_auth_tok - debug function to print auth toks
28 *
29 * This function will print the contents of an ecryptfs authentication
30 * token.
31 */
ecryptfs_dump_auth_tok(struct ecryptfs_auth_tok * auth_tok)32 void ecryptfs_dump_auth_tok(struct ecryptfs_auth_tok *auth_tok)
33 {
34 char salt[ECRYPTFS_SALT_SIZE * 2 + 1];
35 char sig[ECRYPTFS_SIG_SIZE_HEX + 1];
36
37 ecryptfs_printk(KERN_DEBUG, "Auth tok at mem loc [%p]:\n",
38 auth_tok);
39 if (auth_tok->flags & ECRYPTFS_PRIVATE_KEY) {
40 ecryptfs_printk(KERN_DEBUG, " * private key type\n");
41 } else {
42 ecryptfs_printk(KERN_DEBUG, " * passphrase type\n");
43 ecryptfs_to_hex(salt, auth_tok->token.password.salt,
44 ECRYPTFS_SALT_SIZE);
45 salt[ECRYPTFS_SALT_SIZE * 2] = '\0';
46 ecryptfs_printk(KERN_DEBUG, " * salt = [%s]\n", salt);
47 if (auth_tok->token.password.flags &
48 ECRYPTFS_PERSISTENT_PASSWORD) {
49 ecryptfs_printk(KERN_DEBUG, " * persistent\n");
50 }
51 memcpy(sig, auth_tok->token.password.signature,
52 ECRYPTFS_SIG_SIZE_HEX);
53 sig[ECRYPTFS_SIG_SIZE_HEX] = '\0';
54 ecryptfs_printk(KERN_DEBUG, " * signature = [%s]\n", sig);
55 }
56 ecryptfs_printk(KERN_DEBUG, " * session_key.flags = [0x%x]\n",
57 auth_tok->session_key.flags);
58 if (auth_tok->session_key.flags
59 & ECRYPTFS_USERSPACE_SHOULD_TRY_TO_DECRYPT)
60 ecryptfs_printk(KERN_DEBUG,
61 " * Userspace decrypt request set\n");
62 if (auth_tok->session_key.flags
63 & ECRYPTFS_USERSPACE_SHOULD_TRY_TO_ENCRYPT)
64 ecryptfs_printk(KERN_DEBUG,
65 " * Userspace encrypt request set\n");
66 if (auth_tok->session_key.flags & ECRYPTFS_CONTAINS_DECRYPTED_KEY) {
67 ecryptfs_printk(KERN_DEBUG, " * Contains decrypted key\n");
68 ecryptfs_printk(KERN_DEBUG,
69 " * session_key.decrypted_key_size = [0x%x]\n",
70 auth_tok->session_key.decrypted_key_size);
71 ecryptfs_printk(KERN_DEBUG, " * Decrypted session key "
72 "dump:\n");
73 if (ecryptfs_verbosity > 0)
74 ecryptfs_dump_hex(auth_tok->session_key.decrypted_key,
75 ECRYPTFS_DEFAULT_KEY_BYTES);
76 }
77 if (auth_tok->session_key.flags & ECRYPTFS_CONTAINS_ENCRYPTED_KEY) {
78 ecryptfs_printk(KERN_DEBUG, " * Contains encrypted key\n");
79 ecryptfs_printk(KERN_DEBUG,
80 " * session_key.encrypted_key_size = [0x%x]\n",
81 auth_tok->session_key.encrypted_key_size);
82 ecryptfs_printk(KERN_DEBUG, " * Encrypted session key "
83 "dump:\n");
84 if (ecryptfs_verbosity > 0)
85 ecryptfs_dump_hex(auth_tok->session_key.encrypted_key,
86 auth_tok->session_key.
87 encrypted_key_size);
88 }
89 }
90
91 /**
92 * ecryptfs_dump_hex - debug hex printer
93 * @data: string of bytes to be printed
94 * @bytes: number of bytes to print
95 *
96 * Dump hexadecimal representation of char array
97 */
ecryptfs_dump_hex(char * data,int bytes)98 void ecryptfs_dump_hex(char *data, int bytes)
99 {
100 int i = 0;
101 int add_newline = 1;
102
103 if (ecryptfs_verbosity < 1)
104 return;
105 if (bytes != 0) {
106 printk(KERN_DEBUG "0x%.2x.", (unsigned char)data[i]);
107 i++;
108 }
109 while (i < bytes) {
110 printk("0x%.2x.", (unsigned char)data[i]);
111 i++;
112 if (i % 16 == 0) {
113 printk("\n");
114 add_newline = 0;
115 } else
116 add_newline = 1;
117 }
118 if (add_newline)
119 printk("\n");
120 }
121
122