Lines Matching refs:quotient

77 #	0x10(sp) = pointer to location to place quotient/remainder	#
80 #	0x10(sp) = points to location of remainder/quotient.		#
81 #		   remainder is in first longword, quotient is in 2nd.	#
204 	eor.b		%d0, NDIVIDEND(%a6)	# chk if quotient is negative
278 # The quotient is returned in %d6, remainder in %d5, unless the		#
291 # In the general case, four quotient words would be created by
293 # the first two quotient words must be zero, or overflow would occur.
296 # the last two divisions to get a quotient longword and word remainder:
305 	mov.w		%d5, %d1		# first quotient word
312 	mov.w		%d5, %d1		# 2nd quotient 'digit'
315 	mov.l		%d1, %d6		# and quotient
321 # which is divided into a 3 digit (word) dividend to get one quotient
323 # process repeated. Before beginning, the divisor and quotient are
324 # 'normalized' so that the process of estimating the quotient digit
328 	clr.b		DDSECOND(%a6)		# clear flag for quotient digits
329 	clr.l		%d1			# %d1 will hold trial quotient
340 # Now calculate an estimate of the quotient words (msw first, then lsw).
341 # The comments use subscripts for the first quotient digit determination.
348 	mov.w		&0xffff, %d1		# use max trial quotient word
353 	divu.w		%d3, %d1		# use quotient of mslw/msw
358 # now test the trial quotient and adjust. This step plus the
360 # quotient will be at worst 1 too large.
400 	bcc		ldd2nd			# no carry, do next quotient digit
418 # first quotient digit now correct. store digit and shift the
429 # add 2nd word to quotient, get the remainder.
444 	mov.l		DDQUOTIENT(%a6), %d6	# quotient